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9m^2-125m=100
We move all terms to the left:
9m^2-125m-(100)=0
a = 9; b = -125; c = -100;
Δ = b2-4ac
Δ = -1252-4·9·(-100)
Δ = 19225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19225}=\sqrt{25*769}=\sqrt{25}*\sqrt{769}=5\sqrt{769}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-125)-5\sqrt{769}}{2*9}=\frac{125-5\sqrt{769}}{18} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-125)+5\sqrt{769}}{2*9}=\frac{125+5\sqrt{769}}{18} $
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